0.5x^2+0.5=1

Solution for 0.5x^2+0.5=1 equation:

0.5x^2+0.5=1

We move all terms to the left:

0.5x^2+0.5-(1)=0

We add all the numbers together, and all the variables

0.5x^2-0.5=0

a = 0.5; b = 0; c = -0.5;
Δ = b2-4ac
Δ = 02-4·0.5·(-0.5)
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1}{2*0.5}=\frac{-1}{1}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1}{2*0.5}=\frac{1}{1}
=1
$